ayesha67
Answered

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Help please I'll mark you as brainlist if the answer is correct

if (x + q) is a factor of two polynomials x2 + px + q and x2 + mx + n, then prove that a = n-q m-p​

Sagot :

aayushacharya2064

Answer:

factor polynomial is x+q so x=-q

putting the value of x in both equations

eqn 1)a^2+p(-a)+q=0

a^2 -ap+q=0

eqn 2)a^2+m(-a)+n=0

a^2-am+n=0

Since both are equal to zero,we can write:

a^2-ap+q=a^2-am+n

-ap+am=n-q

a(-p+m)=n-q

a=(n-q)/(m-p)

saadatk

Explanation:

Since (x + a) is a factor of the two polynomials, when x = -a, the polynomials should both equal 0 (this is known as the factor theorem).

• First equation:

[tex]x^{2} + px + q[/tex]

When x = -a:

[tex](-a)^{2} + p(-a) + q = 0\\\\a^{2} -pa + q = 0[/tex]

• Second equation:

[tex]x^{2} + mx + n[/tex]

When x = -a:

[tex](-a)^{2} + m(-a) + n = 0\\\\a^{2} -ma + n = 0[/tex]

• As both equations equal 0, we can equate them:

[tex]a^{2} -pa + q = a^{2} -ma + n \\\\-pa + ma = n - q\\\\a(m - p) =n -q\\\\a = (n - q)/ (m - n)[/tex][proven]

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