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Sagot :
Answer:
factor polynomial is x+q so x=-q
putting the value of x in both equations
eqn 1)a^2+p(-a)+q=0
a^2 -ap+q=0
eqn 2)a^2+m(-a)+n=0
a^2-am+n=0
Since both are equal to zero,we can write:
a^2-ap+q=a^2-am+n
-ap+am=n-q
a(-p+m)=n-q
a=(n-q)/(m-p)
Explanation:
Since (x + a) is a factor of the two polynomials, when x = -a, the polynomials should both equal 0 (this is known as the factor theorem).
• First equation:
[tex]x^{2} + px + q[/tex]
When x = -a:
[tex](-a)^{2} + p(-a) + q = 0\\\\a^{2} -pa + q = 0[/tex]
• Second equation:
[tex]x^{2} + mx + n[/tex]
When x = -a:
[tex](-a)^{2} + m(-a) + n = 0\\\\a^{2} -ma + n = 0[/tex]
• As both equations equal 0, we can equate them:
[tex]a^{2} -pa + q = a^{2} -ma + n \\\\-pa + ma = n - q\\\\a(m - p) =n -q\\\\a = (n - q)/ (m - n)[/tex][proven]
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