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Sagot :
(a) The unknown charge kept at distance 0.250m directly below -0.450 charge is 2.315 x 10⁻¹² C.
(b) The magnitude of the force is 29.16 x 10¹² N.
What is electrostatic force?
The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.
F = kq₁q₂/r²
where k = 9 x 10⁹ N.m²/C²
Given is a negative charge -0.450 exerts an upward 0.150N force on an unknown charge 0.250m directly below it .
In equation of the magnitude of force, only the magnitude of charges are taken.
Substituting the values into the expression ,we get the charge
0.150 = (9 x 10⁹ x 0.450x q)/ (0.25)²
q = 2.315 x 10⁻¹² C
Thus, the magnitude of the unknown charge is 2.315 x 10⁻¹² C.
b)Let the unknown charge be 0.450C to exert on -450C.
Substituting the values into the expression ,we get the electrostatic force
F = kq₁q₂/r²
F = (9 x 10⁹ x 0.450x 0.450)/ (0.25)²
q = 2.315 x 10⁻¹² C
Thus, the magnitude of the force is 29.16 x 10¹² N.
Learn more about electrostatic force.
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