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3y > 2x + 12
2x + y ≤ -5

Sagot :

The solution for the inequalities 3y>2x+12, 2x+y<=-5 is the value of x<-27/8 and y<7/4.

Given 3y>2x+12 and 2x+y<=-5.

We are given two inequalities  3y>2x+12 and 2x+y<=-5. Inequality are like equations but in greater than ,less than or in combination with equal to. To solve them we need to first write them properly.

2x-3y<-12

2x+y<=-5

Now assume these are equalities

2x-3y=-12

2x+y=-5

now subtract 2 from 1

2x-3y-2x-y=-12+5

-4y=-7

y=7/4

put the value of y in 2x-3y=-12

2x-3(7/4)=-12

2x-21/4=-12

2x=-12+21/4

2x=(-48+21)/4

2x=-27/4

x=-27/8

Now put the signs between the values

x<-27/8

y<7/4.

Hence the solution of the inequalities 3y > 2x + 12

2x + y ≤ -5 is the value of x<-27/8 and y<7/4.

Learn more about inequality at https://brainly.com/question/11613554

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