Answered

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Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What's
the solution set of this problem?
0 (-2,-21)
0 (-2,-21
O [-21,42)
(21,42)

Sagot :

Answer:

[tex]x \leqslant - 21[/tex]

Step-by-step explanation:

[tex]5(x + 27) \geqslant 6(x + 26)[/tex][tex]5x + 135 \geqslant 6x + 156[/tex]

[tex] - 21 \geqslant x[/tex]

[tex]x \leqslant - 21[/tex]

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