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How many solutions does the equation ||2x-3|-m|=m have if m>0?

Sagot :

varshamittal029

There are three solutions of the equation ||2x-3|-m|=m have if m>0.

We have to estimate the number of solutions of the equation ||2x - 3| - m| = m where m > 0.

As we know in the modulus function

|x|= x if x>0

     -x if x<0

      0 if x=0

here given m > 0

if |2x-3|-m>0 then the modulus value will be ||2x-3|-m|=  |2x-3|-m

Then, |2x - 3| - m = m

⇒|2x - 3| = m+m= 2m

⇒2x - 3 = 2m    or      -(2x-3)=2m

⇒2x - 3 = 2m    or      2x-3=-2m

⇒2x = 3 ± 2m

⇒x = (3 ± 2m)/2

⇒x= (3 + 2m)/2  or   (3 - 2m)/2

If  |2x-3|-m<0 then then the modulus value will be | |2x-3|-m| = -(|2x-3|-m)

-(|2x-3|-m)=m

⇒m-|2x-3|=m

⇒-|2x-3|= m-m

⇒ |2x - 3| = 0

⇒2x = 3

⇒x = 3/2

Therefore The solution of the equation will be (3 + 2m)/2, (3 - 2m)/2, and 3/2.

Therefore there are three solutions of the equation ||2x-3|-m|=m have if m>0.

Learn more about the modulus function

here: https://brainly.com/question/25971887

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