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What is the value of the discriminant of the quadratic equation-2x^2=-8x+8,and what does its value mean about the number of real number solution the equatioj has?

Sagot :

The value of the discriminant is zero and therefore the equation has two equal and real roots.

What is discriminant  ?

For a quadratic Equation ax²+bx+c = 0 , the discriminant is D = b²-4ac

The given quadratic equation is -2x² = -8x+8

comparing with the standard equation

a = 1

b = -4

c = 4

Simplifying the equation given

[tex]\rm -2x^2+8x-8 = 0\\\\ -2(x^2-4x+4) = 0\\\\x^2-4x+4 = 0[/tex]

The discriminant is given by

D = (-4)²-4 * 1 *4

D = 16-16

D = 0

If D = 0 ,the equation has two equal and real roots.

Therefore, The value of the discriminant is zero.

To know more about Discriminant

https://brainly.com/question/15884086

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