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Water is being heated in a closed pan on top of a range while being stirred by a paddle wheel.
During the process, 30 kJ of heat is transferred to the water, and 5 kJ of heat is lost to the
surrounding air. The paddle-wheel work amounts to 500 N · m. Determine the final energy of
the system if its initial energy is 10 kJ.

Sagot :

Heat transfer in a closed system is the addition of changes in internal energy and the total amount of work done by it.  The final energy of the system is 35.5kJ.  

What is heat transfer?

Heat transfer is the transfer of heat energy due to temperature differences.

The paddle-wheel paintings are quantities of workdone, 500 N.m or 0.5kJ.

The preliminary (initial) power of the device is 10 kJ.

Total warmness transferred in the course of the method is 30 kJ

Total warmness misplaced in the course of the method to the encompassing air is 5 kJ.

The energy of the system is given as:

The energy of the system = Energy in - Energy out

The energy of the system = Initial energy + Energy transferred + Work done - Energy lost

Energy of the system = 10 + 30 + 0.5 - 5 kJ

Energy of the system = 35.5 kJ

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