Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
The potential roots of the function p(x)=[tex]x^{3}+6x^{2} -7x-60[/tex] are -10,-5,3,15.
Given function p(x)=[tex]x^{3}+6x^{2} -7x-60[/tex]
We have to find the potential roots of the function according to rational root theorem.
Root is the solution of an equation usually expressed as a number or an algebraic formula.
The rational root theorem is used to find the potential roots of function.
For a polynomial function:
p(x)=p[tex]x^{n}[/tex]+..............................+q
The potential roots are:
Roots =±factors of q/factors of p
Th factors of 60 are =±1,±2,±3,±4,±5,±6,±10,±12.
The factors of 1 is ±1.
So we have factors are:±1,±2,±3,±4,±5,±6,±10,±12,±15,±20/±1
The roots are =±1,±2,±3,±4,±5,±6,±0.
Factors:-10,-5,3,15.
Hence the potential roots are -10,-5,3,15.
Question is incomplete as it should includes options :-10,-7,-5,3,15,24
Learn more about rational root theorem at https://brainly.com/question/10937559
#SPJ4
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.