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A bulldozer does 4,500 j of work to push a mound of soil to the top of a ramp that is 15 m high. the ramp is at an angle of 35° to the ground. how much force did the bulldozer apply to the mound of soil? round your answer to two significant figures. 300 n 370 n 520 n

Sagot :

The bulldozer will apply  520n of force to the mound of soil if the top of a ramp is 15 m high and ramp is at an angle of 35° to the ground.

Given Work = 4500 j , Height of top of a ramp is 15m , the ramp is at an angle 35° to the ground.

Work is the . product of the force vector and displacement vector.

[tex]W=F . x[/tex]

It is the multiplication of magnitudes of the vectors and the vectors and the cosine of the angle between them.

W=F * cos ∅

Displacement of the soil is 15 m . The force is parallel to the ramp. So the angle between the vectors is 90°-35°=55°.

Plugging in the values and solving for F:4500 J =F(15 m)( cos55 °)

F=523N

rounded to the significant figures the force is 520 n.

Hence bulldozer needs to apply force of 520 N.

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