Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
The probability he will get at least 2 hits in the game is 0.470
Given
The batting average is 0.229
In one game he gets 5 at bat
To find the probability he will get at least 2 hits we use binomial distribution.
What is Binomial distribution?
The binomial distribution is also a Frequency distribution used for the possible no. of successful outcomes in a given no. of trials in each of which there is the same probability of success.
So we have
n = 5
p = 0.299
q = 1 - p
= 0.701
[tex]P(X) = nC_{x} p^x q^(n-x)[/tex]
P(at least 2 hits in the game) = 1 - P(less than 2 hits)
= 1 - P(0) - P(1)
[tex]= 1 - 0.701^5 - 5C1 x 0.299 x 0.701^4[/tex]
= 1 - 0.169 - 0.361
= 0.470
Learn more on binomial distribution probability here:
https://brainly.com/question/10559687
#SPJ4
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.