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Sagot :
The beginning and ending energy levels of the electron during the emission of energy that leads to spectral line n(i)= 2 and n(f)=2
calculation :-
(i) Calculation of energy of photon:-
wavelength(λ) = 656.3 nm = 656.3 x 10^-9
E= hc / λ
E = energy of the photon
h=Planck's constant
c=speed of light
λ= wavelength of the photon
E= (6.626 x 10^-34)(3 x 10^8)/( 656.3 x 10^-9)
E = 3.028 x 10^-37J
(ii) Beginning and ending energy levels of the electron during the emission of energy that leads to this spectral line.
It's a red line which means it falls in a visible region which is known as the Balmer series so;
n (f) = 2
ΔE= RH (1/n(f)^2 - 1/n(i)^2)
3.028 x 10^-37 =-2.18 x 10^-18(1/2^2 - 1/n(i))
n(i)= 2
Learn more about energy of the photon here:-
https://brainly.com/question/15946945
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