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Todd and his brother robert are going to use 512 square feet of their backyard for skateboard ramps. the shape of the backyard is rectangular, with the length twice as long as the width. what are the dimensions of the backyard? which quadratic equation would be used to solve for the unknown dimensions? 0 = 2w2 512 = w2 512 = 2w2 512 = 2l 2w

Sagot :

The dimensions are 16  ft by 32 ft

The quadratic equation is w^2-256=0

We have given that,

Todd and his brother Robert are going to use 512 square feet of their backyard for skateboard ramps. the shape of the backyard is rectangular, with the length twice as long as the width.

What is the area of the rectangle?

The area of a rectangle is equal to

A=WL

Where L is the long side of the rectangle

W is the width side of the rectangle

in this problem we have

A=512ft^2

S0,512=LW -----> equation A

L=2W ------> equation B

substitute equation B in equation A

512=2W(W)

512=2w^2

2w^2-512=0

W^2=512/2

W=\sqrt(256)

W=16

Find the value of L

L=2W

L=2(16)

L=32ft

To learn more about rectangle visit:

https://brainly.com/question/25292087

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