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Sagot :
The value of discriminant [tex]b^{2} -4ac[/tex] of the equation [tex]-2x^{2} -3x+8=0[/tex] is equal to 73.
Given equation [tex]-2x^{2} -3x+8=0[/tex] and we have to find the value of determinant and the number of roots of the equation.
Determinant is the quantity that depends on the coefficients of variables.
To find out the value of determinant we have to put the values in [tex]b^{2} -4ac[/tex] in which b=-3, a=-2 and c=8
[tex]b^{2} -4ac[/tex]=[tex]-3^{2} -4*(-2)*8[/tex]
=9+8*8
=9+64
=73
And because the value of discriminant is one so the number of real solution that [tex]-2x^{2} -3x+8=0[/tex] is 2. If the discriminant is equal to zero then there is exactly one real root.
Hence the value of determinant of the equation [tex]-2x^{2} -3x+8=0[/tex] is 73.
Learn more about discriminant at https://brainly.com/question/2507588
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