Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
The value of discriminant [tex]b^{2} -4ac[/tex] of the equation [tex]-2x^{2} -3x+8=0[/tex] is equal to 73.
Given equation [tex]-2x^{2} -3x+8=0[/tex] and we have to find the value of determinant and the number of roots of the equation.
Determinant is the quantity that depends on the coefficients of variables.
To find out the value of determinant we have to put the values in [tex]b^{2} -4ac[/tex] in which b=-3, a=-2 and c=8
[tex]b^{2} -4ac[/tex]=[tex]-3^{2} -4*(-2)*8[/tex]
=9+8*8
=9+64
=73
And because the value of discriminant is one so the number of real solution that [tex]-2x^{2} -3x+8=0[/tex] is 2. If the discriminant is equal to zero then there is exactly one real root.
Hence the value of determinant of the equation [tex]-2x^{2} -3x+8=0[/tex] is 73.
Learn more about discriminant at https://brainly.com/question/2507588
#SPJ4
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
