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Sagot :
Lets simplify the given problem,
The speed with which the plane flies = 350 mph
The direction of flight of the plane = N 40° E
The speed with which the wind blows = 40 mph
The direction in which the wind blows = S 40° E
Therefore, we have;
The resolution of the components of the motion of the plane, given as follows;
= 350 × sin(40°)·i + 350 × cos(40°)·j
The resolution of the components of the motion of the wind, given as follows;
= 40 × sin(40°)·i - 40 × cos(40°)·j
The resultant motion of the plane is given as follows;
= 262.563·i + 254.435·j
The direction of motion of the plane = tan⁻¹(262.563/254.435) ≈ N 45.9° E
Therefore, the plane's drift = Plane's Track - Plane's Heading = N 45.9° E - N 40° E ≈ 5.9° ≈ 5.89°
Drift Angle of the plane is 5.89 degree.
Learn more about motion of plane on:
https://brainly.com/question/2524658
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