Answered

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A certain first-order reaction a → b is 25% complete in 42 min at 25°c. What is the half-life of the reaction?.

Sagot :

Half life of the reaction is :-101.9 min

a→b

25% reacted means 75% remains

t=42 min

Rate constant

k=(2.303/t)(log a/a-x)

k=(2.303/42)(log 100/100-25 )

k=(0.054) (log 100/75)

k=(0.054)(0.1249)

k=0.0068per min

half life

t1/2=(0.693/k)

     =(0.693/0.0068)

     =101.9 min

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