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Sagot :
The value of Z at the 5% level is not significant if the sample of size 400 has mean is 6.0.
What is the standard deviation?
It is defined as the measure of data disbursement, It gives an idea about how much is the data spread out.
[tex]\rm \sigma = \sqrt{\dfrac{ \sum (x_i-X)}{n}[/tex]
σ is the standard deviation
xi is each value from the data set
X is the mean of the data set
n is the number of observations in the data set.
The standard error of the estimated mean:
[tex]\rm = \dfrac{2.5}{\sqrt{400}}[/tex]
= 0.1125
x = 6.0–6.2 = 0.2
[tex]\rm Z = \dfrac{0.2}{0.1125}[/tex]
Z = 1.778
This is not significant at the 5% level.
This would have been significant at the 5% level if the same sample means had been found using a sample size of merely 500.
Thus, the value of Z at the 5% level is not significant if the sample of size 400 has mean is 6.0.
Learn more about the standard deviation here:
brainly.com/question/12402189
#SPJ1
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