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In the following circuit, C1=10.0 F, C2=2*10.0 F, C3=2*10.0 F, C4=2*9.4 F, and
C5=3*9.4. Calculate the equivalent capacitance in the circuit.
Your Answer:

In The Following Circuit C1100 F C22100 F C32100 F C4294 F And C5394 Calculate The Equivalent Capacitance In The Circuit Your Answer class=

Sagot :

The equivalent capacitance in the circuit is 15.05 F.

What is a parallel plate capacitor?

The two parallel plates placed at a distance apart are used to store charge when the electric supply is on.

The capacitance of a capacitor in series is given by:

Series capacitance = 1/ capacitance 1 + 1/ Capacitance2

The capacitance of a capacitor in parallel series can be calculated as:

Parallel capacitance = Capacitance 1 + Capacitance 2

In the following circuit,

C1=10.0 F,

C2=2*10.0 F,

C3=2*10.0 F,

C4=2*9.4 F, and

C5=3*9.4.

In the circuit C2 and C3 are in parallel, their equivalent capacitance is

= 2*10.0 F+2*10.0 F

= 4 *10.0 F

Then, C1 is in series with 4 *10.0 F,

So their equivalent capacitance is

=1 /{ 1/10.0 F + 1/ 4 *10.0 F}

=0.8*10.0 F

C4 and C5 are in series, their equivalent is

=1 /{ 1/2*9.4 F + 1/3*9.4 F}

=0.75*9.4 F

Now,0.8*10.0 F and 0.75*9.4 F are in parallel.

Total equivalent capacitance is Ceq = 0.8*10.0 F + 0.75*9.4 F

Ceq = 15.05 F

Thus, the equivalent capacitance in the circuit is  15.05 F.

Learn more about parallel plate capacitors, here:

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