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Sagot :
The equivalent capacitance in the circuit is 15.05 F.
What is a parallel plate capacitor?
The two parallel plates placed at a distance apart are used to store charge when the electric supply is on.
The capacitance of a capacitor in series is given by:
Series capacitance = 1/ capacitance 1 + 1/ Capacitance2
The capacitance of a capacitor in parallel series can be calculated as:
Parallel capacitance = Capacitance 1 + Capacitance 2
In the following circuit,
C1=10.0 F,
C2=2*10.0 F,
C3=2*10.0 F,
C4=2*9.4 F, and
C5=3*9.4.
In the circuit C2 and C3 are in parallel, their equivalent capacitance is
= 2*10.0 F+2*10.0 F
= 4 *10.0 F
Then, C1 is in series with 4 *10.0 F,
So their equivalent capacitance is
=1 /{ 1/10.0 F + 1/ 4 *10.0 F}
=0.8*10.0 F
C4 and C5 are in series, their equivalent is
=1 /{ 1/2*9.4 F + 1/3*9.4 F}
=0.75*9.4 F
Now,0.8*10.0 F and 0.75*9.4 F are in parallel.
Total equivalent capacitance is Ceq = 0.8*10.0 F + 0.75*9.4 F
Ceq = 15.05 F
Thus, the equivalent capacitance in the circuit is 15.05 F.
Learn more about parallel plate capacitors, here:
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