Answer + Step-by-step explanation:
[tex]f(x) = 5|x-6|+2 = \begin{cases}5\left( x-6\right) +2&if\ x\geq 6\\ 5\left( 6-x\right) +2 &if\ x\leq 6\end{cases}[/tex]
[tex]\Longrightarrow f(x) = \begin{cases}5x-30+2&if\ x\geq 6\\ 30-5x +2 &if\ x\leq 6\end{cases}[/tex]
[tex]\Longrightarrow f(x) = \begin{cases}5x-28&if\ x\geq 6\\ -5x +32 &if\ x\leq 6\end{cases}[/tex]
case 1: x ≥ 6 → f(x) = 5x - 28
5(6) - 28 = 30 - 28 = 2
Then
the point A(6 ,2) lie on the graph (line) of f
5(7) - 28 = 35 - 28 = 7
Then
the point B(7 ,7) lie on the graph (line) of f
Graphing :
When x ≥ 6 ,the graph of f is the ray [AB) (just connect the points A and B)
case 2: x ≤ 6 → f(x) = -5x + 32
-5(6) +32 = -30 + 32 = 2
Then
the point A(6 ,2) lie on the graph (line) of f
-5(5) +32 = -25 + 32 = 7
Then
the point C(5 ,7) lie on the graph (line) of f
Graphing :
When x ≤ 6 ,the graph of f is the ray [AC) (just connect the points A and C)
