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0.3 y+\dfrac yz0.3y+
z
y

0, point, 3, y, plus, start fraction, y, divided by, z, end fraction when y=10y=10y, equals, 10 and z=5z=5


Sagot :

The required solution to the equation is [tex]0.3y+\frac{y}{z}[/tex] at y=10, z=5 is 5.

As we have the equation [tex]0.3y+\frac{y}{z}[/tex] and find solution At y =10 and z=5

What is equation?

The equation is the relationship between dependent and independent variables through some mathematical operators.

Now,
      putting the value of  y=10, z=5 in [tex]0.3y+\frac{y}{z}[/tex]
  ⇒[tex]0.3*10+\frac{10}{5}[/tex]
   =  5

Thus the required value of the equation at y=10 and z =5 is 3.

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