Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
The running speed of Jenny willl be 2.5 times the velocity she walks.
What is velocity?
The change of distance concerning to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
Condition 1;
She takes 25 minutes to run 1,000 m and walk 1,600 m The total time to run as well as the walk is 25 minutes.
[tex]\rm t = t_r +t_w \\\\ 25 = t_r +t_w[/tex]
As we know that;
Distance = speed × time
[tex]\rm x_r = v_r \times t_r \\\\ t_r = \frac{x_r}{v_r}[/tex]
For walking;
[tex]\rm t_w = \frac{x_w}{v_w}[/tex]
[tex]\rm t = t_r +t_w \\\\ 25 = \frac{x_r}{v_r} +\frac{x_w}{v_w} \\\\ 25 = \frac{1000 \ m}{v_r} +\frac{1600 \ }{v_w} \\\\ 40 v_w +64 v_r = v_rv_w[/tex]
Same as for condition 2;
[tex]\rm 100 v_w + 40 v_r = v_rv_w[/tex]
[tex]\rm 40 v_w +64 v_r =\rm 100 v_w + 40 v_r \\\\ v_r = 2.5 v_w[/tex]
Condition 3;
[tex]\rm d_w = 800 \ m[/tex]
[tex]\rm d_w = v_w \times t_w[/tex]
[tex]\rm t_w = \frac{d_w}{v_w } \\\\ \rm t_w = \frac{800}{v_w } \\\\[/tex]
Hence their running speed of Jenny willl be 2.5 times the velocity at she walks.
To learn more about the velocity, refer to the link: https://brainly.com/question/862972.
#SPJ1
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.
