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What is the equation of the parabola? coordinate plane with a parabola facing up with vertex at 0 comma 2, the point 0 comma 5 and a horizontal line going through 0 comma negative 1 y = −one twelfthx2 − 2 y = one twelfthx2 − 2 y = −one twelfthx2 2 y = one twelfthx2 2

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MrRoyal

The equation of the parabola is y = 2/25x^2 + 2

How to determine the parabola equation?

The complete question is in the image

The given parameters are:

Vertex, (h, k) = (0,2)

Point (x,y) = (-5, 4)

The parabola is represented as;

y = a(x - h)^2 + k

Substitute (h, k) = (0,2)

y = a(x - 0)^2 + 2

This gives

y = ax^2 + 2

Substitute (x, y) = (-5,4)

4 = a(-5)^2 + 2

This gives

4 = 25a + 2

Subtract 2 from both sides

25a = 2

Divide by 25

a = 2/25

Substitute a = 2/25 in y = ax^2 + 2

y = 2/25x^2 + 2

Hence, the equation of the parabola is y = 2/25x^2 + 2

Read more about parabola at:

https://brainly.com/question/1480401

#SPJ1

View image MrRoyal
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