Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
The rate of change of [tex]SO_2[/tex](g)=0.024M/s when the rate of change of [tex]CS_2(g)[/tex] is – 0.012 M/s.
What is the rate of reaction?
Reaction rate, in chemistry, is the speed at which a chemical reaction proceeds.
[tex]CS_2(l)+3O_2(g)[/tex] → [tex]CO_2(g)+2SO_2(g)[/tex]
[tex]Rate = \frac{-dcs_2}{dt} =\frac{-do_2}{dt} =\frac{+dco_2}{dt} =\frac{1dso_2}{dt}[/tex]
Rate = \frac{-dcs_2}{dt} =\frac{-do_2}{dt} =\frac{+dco_2}{dt} =\frac{1dso_2}{dt}
Given:
[tex]\frac{-dcs_2}{dt} =-0.012 M/s[/tex]
[tex]\frac{-dcs_2}{dt} =\frac{dso_2}{dt}[/tex]
[tex]\frac{dso_2}{dt}=0.024M/s[/tex]
The rate of change of [tex]SO_2[/tex](g)=0.024M/s
Hence, the rate of change of [tex]SO_2[/tex](g)=0.024M/s
Learn more about the rate of change here:
https://brainly.com/question/13103052
#SPJ1
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.