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Consider the reaction, CS2(l)+3O2(g)→CO2(g)+2SO2(g) . The rate of change of CS2(g) is – 0.012 M/s . What is the rate of change of SO2(g) ?

Sagot :

The rate of change of [tex]SO_2[/tex](g)=0.024M/s when the rate of change of [tex]CS_2(g)[/tex] is – 0.012 M/s.

What is the rate of reaction?

Reaction rate, in chemistry, is the speed at which a chemical reaction proceeds.

[tex]CS_2(l)+3O_2(g)[/tex] → [tex]CO_2(g)+2SO_2(g)[/tex]

[tex]Rate = \frac{-dcs_2}{dt} =\frac{-do_2}{dt} =\frac{+dco_2}{dt} =\frac{1dso_2}{dt}[/tex]

Rate = \frac{-dcs_2}{dt}  =\frac{-do_2}{dt} =\frac{+dco_2}{dt} =\frac{1dso_2}{dt}

Given:

[tex]\frac{-dcs_2}{dt} =-0.012 M/s[/tex]

[tex]\frac{-dcs_2}{dt} =\frac{dso_2}{dt}[/tex]

[tex]\frac{dso_2}{dt}=0.024M/s[/tex]

The rate of change of [tex]SO_2[/tex](g)=0.024M/s

Hence, the rate of change of [tex]SO_2[/tex](g)=0.024M/s

Learn more about the rate of change here:

https://brainly.com/question/13103052

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