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Sagot :
The answer to the question is 0.8055 as the answer should not include units in it.
Molarity (M) = n/v
n = moles of solute
v = liters of solution
According to question
1% solution → 1 gram of solute for 100 milliliters of solution
2% solution → 2 grams of solute for 100 milliliters of solution
6% NaClO solution → 6 grams of NaClO (solute) for 100 milliliters of solution
Molar mass of NaClO = (22.98 + 35.5 + 16)g/mol = 74.48 g/mol
Atomic mass of Na = 22.98 g/mol
Atomic mass of Cl = 35.5 g/mol
Atomic mass of O = 16 g/mol
1 mol NaClO = 74.48 grams NaClO
74.48 grams NaClO = 1 mol NaClO
6 grams NaClO = (1×6) / 74.48 mole = 0.08055 mole
As unit molarity is mole / liter
So 100 milliliters = 0.1 liters
1 liter = 1000 milliliters
100 milliliters = 100/1000 liters = 0.1 liters
Molarity of NaClO = moles of solute (NaClO) / liters of solution or volume of solution
Molarity of NaClO = 0.08055 / 0.1 mole/L = 0.8055 mole/L
As in question it is mentioned that 'Do not type units into your answer'
So, Molarity of NaClO in clorox bleach = 0.8055
Thus we find out the value of molarity of NaClO in Clorox bleach which came out to be 0.8055 as we dont have to give the answer with units.
Learn more about Molarity here:
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