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Sagot :
The average acceleration of snowboarder's is 0.19 m/s² and distance travel by snowboarder is 6.70 metres.
We have given that snowboarder start moving from rest means
Initial speed (u) = 0 m/s
Final speed (v) = 1.6 m/s
time taken (t) = 8.4 s
Applying first equation of motion
v = u + at
1.6 = 0 + a×8.4
1.6 = 8.4a
a = 1.6/8.4 m/s²
a = 0.19 m/s²
So average acceleration is 0.19 m/s².
Now Applying second equation of motion
s = ut + 1/2at²
s = (0) × (8.4) + (1/2)(0.19)(8.4)² metre
s = (1/2)(0.19)(8.4)² metre
s = 6.70 metre
So that distance covered by snowboarder is 6.70 metre.
So we find out the average acceleration by using first equation of motion and the average acceleration came out to be 0.19 m/s² and to find out the distance covered by snowboarder we use second equation of motion and the distance came out to be 6.70 metre.
Learn more about equations of motion here:
https://brainly.com/question/27899272
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