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The average price of a personal computer (PC) is $949. If the computer prices are approximately normally distributed and standard deviation is $100, what is the probability that a randomly selected PC costs more than 1200? The least expensive 10% of personal computers cost less than what amount?

Sagot :

The probability that a randomly selected PC costs more than 1200 will be 0.006. The least expensive 10% of personal computers cost less than what amount will be 820.8.

What is a normal distribution?

The Gaussian distribution is another name for it. The most significant continuous probability distribution is this one. Because the curve resembles a bell, it is also known as a bell curve.

The z-score is given as

z = (x – μ) / σ

Where μ is the mean, σ is the standard deviation, and x is the sample.

The average price of a personal computer (PC) is $949.

If the computer prices are approximately normally distributed and standard deviation is $100.

Then the probability that a randomly selected PC costs more than 1200 will be

z = (1200 – 949) / 100

z = 2.51

Then  the probability will be

P(x > 1200) = P(z > 1200)

P(x > 1200) = 1 – P(z < 1200)

P(x > 1200) = 1 – 0.99396

P(x > 1200) = 0.0060366

The least expensive 10% of personal computers cost less than what amount will be

z-value for 10% will be -1.282.

– 1.282 = (x – 949) / 100

– 128.2 = x – 949

          x = 820.8

More about the normal distribution link is given below.

https://brainly.com/question/12421652

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