Answered

Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Every weekend me and my brother and my cousin go outside to play basketball and when i was the one who will shoot the ball to the ring i used the things i learned in math so I use SOH-CAH-TOA in measuring it. I want to measure the distance between me and the basketball ring. Supposed the height of the ring is 8ft from the ground and the distance between me and the basketball ring horizontally is 11.5 ft, and the angle of elevation from the ground is 50 degrees, now what is the distance of me and the ring?
Let x be the distance between me and the ring

need urgent answers with equation
by using SOH from SOHCAHTOA

Every Weekend Me And My Brother And My Cousin Go Outside To Play Basketball And When I Was The One Who Will Shoot The Ball To The Ring I Used The Things I Learn class=

Sagot :

Answer:

10 . 44 ft

Step-by-step explanation:

sin 50 = opposite leg / hypotenuse = 8 / x

8 / sin 50 = x    = 10 .44  ft

tanweeleong195oxyqwp

Answer:

10.433cm

Step-by-step explanation:

Using SOH from TOACAHSOH,

[tex]sin50deg = \frac{opposite}{hypotenuse} [/tex]

From here we know there the opposite is 8ft (height of the ring) and hypotenuse is what we want to find, distance between you and the ring.

[tex]sin(50) = \frac{8}{x} \\ x \sin(50) = 8 \\ x = \frac{8}{ \sin(50) } \\ x = 10.443cm(rounded \: to \: 5sf)[/tex]

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.