Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Review the work showing the first few steps in writing a partial fraction decomposition.


StartFraction 4 x + 40 Over (x + 2) (x + 6) EndFraction = StartFraction A Over x + 2 EndFraction + StartFraction 16 Over x + 6 EndFraction


4x + 40 = A(x + 6) + B(x + 2)


4x + 40 = Ax + 6A + Bx + 2B


What is the partial fraction decomposition in terms of x?


StartFraction 4 x + 40 Over (x + 2) (x + 7) EndFraction = StartFraction negative 12 Over x + 2 EndFraction + StartFraction 16 Over x + 6 EndFraction

StartFraction 4 x + 40 Over (x + 2) (x + 7) EndFraction = StartFraction negative 4 Over x + 2 EndFraction + StartFraction 8 Over x + 6 EndFraction

StartFraction 4 x + 40 Over (x + 2) (x + 7) EndFraction = StartFraction 8 Over x + 2 EndFraction + StartFraction negative 4 Over x + 6 EndFraction

StartFraction 4 x + 40 Over (x + 2) (x + 7) EndFraction = StartFraction 16 Over x + 2 EndFraction + StartFraction negative 12 Over x + 6 EndFraction


The Answer is C


Sagot :

StartFraction 4 x + 40 Over (x + 2) (x + 7) EndFraction = StartFraction 8 Over x + 2 EndFraction + StartFraction negative 4 Over x + 6 EndFraction

What is partial fraction?

Partial fractions are the fractions used for the decomposition of a rational expression.

Given:

(4x + 40)/ (x + 2)(x + 6) = A/(x + 2) + B/(x + 6)

4x + 40 = A(x + 6) + B(x + 2)

4x + 40 = x(A+B) + 6A +2B

On comparing

4= A+B

A= 4-B

and, 6A +2B =40

3A + B =20

3(4-B) + B =20

12  - 3B + B =20

-2B = 8

B= -4

and, A= 8

Hence, StartFraction 4 x + 40 Over (x + 2) (x + 7) EndFraction = StartFraction 8 Over x + 2 EndFraction + StartFraction negative 4 Over x + 6 EndFraction

Learn more about this concept here:

https://brainly.com/question/27156476

#SPJ1