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Find a degree 3 polynomial having zeros -4, 3 and 8 and the coefficient of x 3 equal 1.

Sagot :

The required polynomial is [tex]x^{3}-7x^{2} -20x+96[/tex]

Polynomial : If in an expression all of variables, constants and exponents are present with mathematical operations like addition, multiplication, subtraction & division, then it is called polynomial.

If a polynomial has degree 3 as a highest degree, then the polynomial is called degree 3 polynomial or cubic polynomial.

A degree 3 polynomial having zeros α, β, γ and the coefficient of x³ equal a is,  a(x- α)(x- β)(x- γ)

Given, Zeros of the polynomial are -4, 3, 8 & coefficient of x³ equal 1.

Hence, the required polynomial is,

[tex]1(x-(-4))(x-3)(x-8)[/tex]

[tex](x+4)(x-3)(x-8)[/tex]

[tex]=(x+4)(x^{2} -11x+24)[/tex]

[tex]=x^{3}-11x^{2} +24x+4x^{2} -44x+96[/tex]

[tex]=x^{3}-7x^{2} -20x+96[/tex]

This is a degree 3 polynomial.

Learn more about polynomial here :

https://brainly.com/question/1379486

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