Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
The time after it starts spinning, that the box will slip off is 0.1 s.
Apply the principle of conservation of angular momentum
I₁ω₁ - I₂ω₂ = 0
I₁ω₁ = I₂ω₂
where;
- I₁ is initial moment of inertia
- I₂ is final moment of inertia
- ω₁ is initial angular speed
- ω₂ is final angular speed
The final angular speed when the box slides off;
ω₂ = I₁ω₁ / I₂
ω₂ = [0.5(m₁ + m₂)(R + r)²] / (0.5MR²)
ω₂ = [0.5(30 + 0.3)(3.1 + 1.4)²] / (0.5 x 30 x 3.1²)
ω₂ = 2.13 rad/s
Time taken for the for box to slide off;
τ = Iα
τ = I(ω/t)
τ = (Iω)/t
t = (Iω)/τ
t = (0.5 x 0.3 x 1.4² x 2.13)/6
t = 0.1 s
Thus, the time after it starts spinning, that the box will slip off is 0.1 s.
Learn more about moment of inertia here: https://brainly.com/question/3406242
#SPJ1
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.