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Part 2 - Find the error(s) and solve the problem correctly.

Part 2 Find The Errors And Solve The Problem Correctly class=

Sagot :

The error is present in second step when cancelling numerator and denominator and the solution of the expression [tex](1+1/x)/(1-1/x^{2} )[/tex] is [tex]x/x-1[/tex].

Given Expression [tex](1+1/x)/(1-1/x^{2} )[/tex] and incorrect solution. and we need to identify the error and solve the expression correctly.

The expression is [tex](1+1/x)/(1-1/x^{2} )[/tex]

In the solution given the second step of cancelling 1's in numerator and denominator is wrong.

The solution which is correct is as under:

[tex](1+1/x)/(1-1/x^{2} )[/tex]

firstly take LCM in numerator and denominator

=[tex](x+1)/x/(x^{2} -1)/x^{2}[/tex]

Now we can write the expression properly.

=[tex](x+1)*x^{2} /(x^{2} -1)*x[/tex]

Power of [tex]x^{2}[/tex] to be deducted from x

=[tex](x+1)*x/(x^{2} -1)[/tex]

Now [tex]x^{2} -1[/tex] can be written as (x+1)(x-1)

=[tex](x+1)*x/(x+1)(x-1)[/tex]

(x+1) will be deducted now from numerator and denominator.

=x/(x-1)

Hence the solution of the given expression is x/(x-1).

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The answer to this question is x/x₋1

Given the expression is 1₊1/x /1₋1/x²

Take the LCM of the denominators

we get, x₊1/x / x²₋1/x²

Now multiply the expression

=x₊1/x × x²/x²₋1

=(x₊1) x²/ x(x²₋1)

(x²₋1) is in the form of (a²₋b²)=(a₊b)(a₋b)

Therefore, (x₊1)x²/x(x₋1)(x₊1)

After cancelling like terms we get the answer as:

x/(x₋1)

Hence we get the simplification answer as x/(x₋1).

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