bmijares9
Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

I NEED HELP! A rigid cylinder contains 3.00 liters of gas at a temperature of 25°C. If the pressure of this gas is changed from
0.500 atmospheres to 1.50 atmospheres, what will be the new temperature of the gas? (R= 0.0821 Latm/mol K)
O 612 °C
894 °C
99.3 °C
885 °C
O 75.0 °C

Sagot :

indrawboy

Gay Lussac's Law

P₁/T₁=P₂/T₂

25°C = 25+273 = 298 K

0.5/298 = 1.5/T₂

T₂ = 894 K = 621 °C

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.