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Find the solution set for this equation:
-a2+4a=0
(Separate the two values with a comma)


Sagot :

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: \{ 0,4 \}[/tex]

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[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: - {a}^{2} + 4a = 0[/tex]

[tex]\qquad \tt \rightarrow \: - ( {a}^{2} - 4a) = 0[/tex]

[tex]\qquad \tt \rightarrow \: {a}^{2} - 4a = 0[/tex]

[tex]\qquad \tt \rightarrow \:a(a - 4) = 0[/tex]

The two cases are :

  • a = 0

or

  • a -4 = 0, that leads to a = 4

We can conclude :

[tex]\qquad \tt \rightarrow \:solution \: (a) = \{ 0,4\}[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

[tex] \quad \quad \quad \quad\huge \tt \pink ❆ AnSweR \pink ❆[/tex]

[tex]\quad\quad \tt-a^2+4a= 0[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex] \quad\quad\tt⇢-1(a^2 - 4a) = 0[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex]\quad\quad\tt⇢-1(a-4)a = 0[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex]\quad\quad\tt⇢a-4=0[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex]\quad\quad\tt⇢a = 0[/tex]

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[tex] \boxed{ \tt \blue{a = 0}}[/tex]

[tex]\boxed{ \tt\blue{a = 4}}[/tex]