Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Answer:
Empirical: NO2. Molecular: N2O4
Explanation:
In order to determine the empirical formula, we divide each element's mass by their respective molar mass:
N: 0.3955g/14.01 g/mol = 0.02823 mol
O: 0.904g/16.00 g/mol = 0.0565 mol
Next, we take the smallest value and multiply it till it is close enough to an integer:
0.02823 x 40 = 1.12 Close enough to 1.
0.0565 x 40 = 2.26. Close enough to 2.
Therefore, the Empirical Formula is: NO2
Next, we determine how much the Empirical formula weighs and see if it matches 92g/mol:
14.01 g/mol + 2(16.00 g/mol) = 46.01 g/mol
We can assume this is roughly half of 92 g/mol so we can multiply each subscript by 2 to match the weight.
Therefore, the Molecular formula is N2O4
Hope this helped!
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
