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Find the slope of the line that contains the points (-8, -2) and (-17, 4).

Sagot :

Answer:

-2/3

Step-by-step explanation:

m=y2-y1/x2-x1
m=4-(-2)/-17-(-8)
m=4+2/-17+8
m=6/-9
m=-2/3

SOLVING

[tex]\Large\maltese\underline{\textsf{A. \space What is Asked}}[/tex]

Find the slope of the line that contains the points (-8,-2) and (-17,4)

[tex]\Large\maltese\underline{\textsf{B.\space This problem has been solved!}}[/tex]

If we are given two points, we can easily find the slope of the line that passes through the points. With points (y₂, y₁) and (x₂, x₁), the slope is [tex]\bf{\dfrac{y2-y1}{x2-x1}[/tex].

Similarly, with points (-8,-2) and (-17,4) the slope is.

[tex]\bf{\dfrac{4-(-2)}{-17-(-8)}}[/tex] | as we can see, it is possible to simplify this further

[tex]\bf{\dfrac{4+2}{-17+8}}[/tex] | simplify

[tex]\bf{\dfrac{6}{-9}[/tex] | reduce

[tex]\bf{-\dfrac{2}{3}}[/tex]

[tex]\rule{300}{1.7}[/tex]

[tex]\bf{Result:}[/tex]

                    [tex]\bf{=-\dfrac{2}{3}}[/tex]

[tex]\boxed{\bf{aesthetic\not101}}[/tex]

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