Answered

Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

a steel ring is 50mm diameter and 2mm thick. it must be fitted onto a shaft 50.04 mm diameter. calculate the temperature to which it must be heated in order to fit the shaft. the initial temperature is 20 deg C and the coefficient of linear expansion is 15x10^-6 per degrees celcius. calculate the stress and forced induced in the ring

okay so the stress and forced induced I can do that but the first part is confusing me because there is no final temperature.

Sagot :

onyebuchinnaji

The temperature to which it must be heated in order to fit the shaft is 73.33 ⁰C.

Linear expansivity

The temperature to which it must be heated in order to fit the shaft is calculated as follows;

[tex]\frac{\Delta L}{L} = \alpha \Delta T\\\\\Delta T = \frac{\Delta L}{\alpha L}[/tex]

where;

  • ΔT is change in temperature
  • ΔL is change in length = 50.04 mm - 50 mm = 0.04 mm
  • α is coefficient of linear expansion
  • L is original length

ΔT = (0.04)/(50 x 15 x 10⁻⁶)

ΔT = 53.3 ⁰C

Final temperature

T₂ - T₁ = ΔT

T₂ = ΔT + T₁

where;

  • T₂ is final temperature
  • T₁ is initial temperature

T₂ = 53.3 + 20

T₂ = 73.33 ⁰C

Learn more about linear expansivity here: https://brainly.com/question/14325928

#SPJ1

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.