hernandez6793
Answered

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Find the vertex of the function given below.
y= 2x² + 8x+1
A. (-2,-7)
B. (-2,-1)
OC. (3,-4)
D. (1,7)

Sagot :

Answer:

A

Step-by-step explanation:

given a quadratic function in standard form

y = ax² + bx + c (a ≠ 0 ) then the x- coordinate of the vertex is

x = - [tex]\frac{b}{2a}[/tex]

y = 2x² + 8x + 1 ← is in standard form

with a = 2 , b = 8 , then

x = - [tex]\frac{8}{4}[/tex] = - 2

substitute x = - 2 into the equation for corresponding y- coordinate

y = 2(- 2)² + 8(- 2) + 1 = 2(4) - 16 + 1 = 8 - 16 + 1 = - 7

vertex = (- 2, - 7 )

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