Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Which is the equation in slope-intercept form for the line that passes through (−2, 15) and is perpendicular to 2x + 3y = 4?


y=−32x+18

y=32x−12

y=23x+18

y=32x+18


Sagot :

The linear equation that respects the given conditions is:

[tex]y = \frac{3}{2}x + [/tex]

What is a linear function?

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

When two lines are perpendicular, the multiplication of their slopes is of -1. Hence, considering it is perpendicular to 2x + 3y = 4.

[tex]2x + 3y = 4[/tex]

[tex]3y = -2x + 4[/tex]

[tex]y = -\frac{2x}{3} + \frac{4}{3}[/tex]

Then:

[tex]-\frac{2}{3}m = -1[/tex]

[tex]m = \frac{3}{2}[/tex]

Hence:

[tex]y = \frac{3}{2}x + b[/tex]

It passes through (−2, 15), that is, when x = -2, y = 15, hence:

[tex]y = \frac{3}{2}x + b[/tex]

[tex]15 = \frac{3}{2}(-2) + b[/tex]

15 = -3 + b

b = 18.

So the equation is:

[tex]y = \frac{3}{2}x + [/tex]

More can be learned about linear functions at https://brainly.com/question/24808124

#SPJ1