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Sagot :
Answer: 50%
Explanation:
To find the percent composition of oxygen in SO₂, we need to find out the molar masses of both elements and add them.
First, figure out how many atoms are in each element of this compound. Then figure out the molar mass by multiplying it by the molar mass you'd see on the periodic table.
[tex]1atomS*32.06g=32.06g/molS\\2atomO*15.999g=31.998g/molO_{2}[/tex]
Now that we have that information, we must add up the numbers to get the molar mass of SO₂.
[tex]32.06g/molS+31.998g/molO_{2} =64.058g/molSO_{2}[/tex]
Now we have the molar mass of SO₂. To find the percent composition of oxygen in SO₂, we must divide the molar mass of O₂ by that of SO₂, then multiply that by 100.
[tex]\frac{31.998g/molO_{2} }{64.058g/molSO_{2} } *100=49.95; 50[/tex]
Given this, the percent composition of oxygen in SO₂ is 50%.
I hope this helps! Pls mark brainliest!! :)
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