devoniaseymour8
Answered

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A line passes through the point (-2, 8) and has a slope of-5/2.
Write an equation in slope-intercept form for this line.

Sagot :

amysun2025

Answer:

[tex]y = -\frac{5}{2} x + 3[/tex]

Step-by-step explanation:

We are given that a line passes through (-2, 8) and has a slope of -5/2.

We want to write the equation of this line in slope-intercept form.

Slope-intercept form is given as y=mx+b, where m is the slope and b is the value of y at the y-intercept.

Since we are already given the slope of this line, we can immediately plug it into the equation.

Replace m with -5/2.

[tex]y = -\frac{5}{2} x+ b[/tex]

Now we need to find b.

As the equation passes through the point (-2, 8), we can use its values to help solve for b.

Substitute -2 as x and 8 as y.

[tex]8 = -\frac{5}{2} (-2) +b[/tex]

Multiply.

8 = 5 + b

Subtract 5 from both sides.

3 = b

Replace b with 3 in the equation.

[tex]y = -\frac{5}{2} x + 3[/tex]

Topic: finding the equation of the line (slope-intercept form)

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