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Sagot :
The age of the man whose normal pressure measures 128 mmHg is approximately 38 years.
How do we determine the age of the man using a quadratic equation?
The quadratic formula can be used to determine the age of a man whose normal blood pressure measures 128 mmHg. This can be expressed mathematically as:
[tex]\mathbf{ \dfrac{-b \pm\sqrt{b^2 - 4ac}}{2a}}[/tex]
From the given equation:
P = 0.006A² - 0.02A + 120
where;
- P = 128
128 = 0.006A² - 0.02A + 120
= 0.006A² - 0.02A + 120 - 128
= 0.006A² - 0.02A - 8
where:
- a = 0.006 , b = - 0.02, and c = -8
[tex]\mathbf{ \dfrac{-(-0.02) \pm\sqrt{(-0.02)^2 - 4(0.006)(-8)}}{2(0.006)}}[/tex]
[tex]\mathbf{ = \dfrac{(0.02) \pm 0.43863}{0.012}}[/tex]
= 38.2195 or -34.8862
Taking the positive integer value, the age of the man whose normal pressure measures 128 mmHg is approximately 38 years.
Learn more about using the quadratic formulas to solve quadratic equations here:
https://brainly.com/question/8649555
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