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fieryanswererft

Answer:

The distance is 7.3 units.

Step-by-step explanation:

Two given points: (-3, 1) and (4, -1)

[tex]\sf Distance \ between \ two \ points = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]

Here given:

  • x₂ = 4
  • x₁ = -3
  • y₂ = -1
  • y₁ = 1

Applying the formula:

[tex]\sf d = \sqrt{(4 - (-3))^2 + (-1 - 1)^2}[/tex]

[tex]\sf d = \sqrt{(7)^2 + (-2)^2}[/tex]

[tex]\sf d = \sqrt{49 + 4}[/tex]

[tex]\sf d = \sqrt{53} \ \approx \ 7.28 \ \approx \ 7.3 \ (rounded)[/tex]

rvkacademic

Answer:

7.3

Step-by-step explanation:

The distance of a line segment between two points (x1, y1) and (x2, y2) is given by the formula

[tex]d = \sqrt{(x2-x1)^2 + (y2-y1)^2}[/tex]

If we look at the graph,

the leftmost point of the line is at (-3, 1). Let's call this (x1, y1)

the rightmost point is at (4, -1). Let's call this (x2, y2)

Substituting these values into the distance formula gives us


[tex]d = \sqrt{(4-(-3)^2 + (1-(1)^2} \\ \\d = \sqrt{(7)^2 + (-2)^2} \\ \\d = \sqrt{49 + 4} \\\\d = \sqrt{(x2-x1)^2 + (y2-y1)^2}\\\\d = \sqrt{53} = 7.28[/tex]

Rounded to one decimal place, this is 7.3

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