jasminesykes2007
Answered

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help meeeeeee please​

Help Meeeeeee Please class=

Sagot :

Answer: 4/9

Possible number of pairs given cards:
3*3=9

Number of sum with odd score, two odd numbers added to an even number from each box:
2*1+1*2=4 (pairs of 3 and 5 with 2 or pairs of 9 and 3 with 4)

Required probability:
P(odd)=4/9
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