Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

help meeeeeee please​

Help Meeeeeee Please class=

Sagot :

Answer: 4/9

Possible number of pairs given cards:
3*3=9

Number of sum with odd score, two odd numbers added to an even number from each box:
2*1+1*2=4 (pairs of 3 and 5 with 2 or pairs of 9 and 3 with 4)

Required probability:
P(odd)=4/9