Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

A scientist has 50 grams of a radioactive element. The amount of radioactive element remaining after t days can be
determined using the equation f()-50
50 (1) ³ . After two days the scientist receives a second shipment of 50 grams of the
same element. The equation used to represent the amount of shipment 2 remaining after t days is f(t)-50
(1)- 50 (2)
of the following is an equivalent form of the expression for the amount remaining in shipment 2?
•(9²
5
50.
19
t
50-(³

Sagot :

Martebi

The option that is the equivalent form of the expression for the amount remaining in shipment 2 is the second option: 50 ([tex]\frac{1}{2} ^ \frac{t}{5} / \frac{1}{2} ^ \frac{2}{5}[/tex])

What is the radioactive element about?

Note that:

f(t)= 50 (1/2)^ [tex]\frac{t-2}{5}[/tex]

f(t)= 50 (1/2)^ [tex]\frac{\frac{t}{5} } - {\frac{2}{5} }[/tex]

Note also that in indices,  [tex]x^{-y}[/tex] = 1/ [tex]x^{y}[/tex]

Then:  50 ([tex]\frac{1}{2} ^ \frac{t}{5} / \frac{1}{2} ^ \frac{2}{5}[/tex])

([tex]50 \frac {1}{2} ^ \frac{t}{5} / \frac{1}{2} ^ \frac{2}{5}[/tex])

= 50 ([tex]\frac{1}{2} ^ \frac{t}{5} / \frac{1}{2} ^ \frac{2}{5}[/tex])

Therefore, The option that is the equivalent form of the expression for the amount remaining in shipment 2 is the second option: 50 ([tex]\frac{1}{2} ^ \frac{t}{5} / \frac{1}{2} ^ \frac{2}{5}[/tex])

Learn more about radioactive element from

https://brainly.com/question/25799605

#SPJ1

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.