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A collection of coins has a value of 64 cents. There are two more nickels than dimes and three times as many pennies as dimes. How many of each kind of coin are there?

Sagot :

There are 5 nickels, 3 dimes, and 9 pennies.

Let d = The number of dimes

Let n = number of nickels

Let p = The number of pennies

As given, there are two more nickels than dimes and three times as many pennies as dimes:

d+2=n

3d=p

0.10d+0.05n+0.01p=0.64

Plug in the value to find d

[tex]0.10d+0.05(d+2)+0.01(3d)=0.64[/tex]

[tex]0.10d+0.05d+0.1+0.03d=0.64[/tex]

[tex]0.18d=0.64[/tex]

[tex]d=3[/tex]

What is the value of p?

The value of p is equal to 3d

p=3(3)=9

n=d+2

n=3+2

n=5

Hence, there are 5 nickels, 3 dimes, and 9 pennies.

To learn more about the collection visit:

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