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If −6x+y=−4 and −8x−10y=3 are true equations, what would be the value of 2x+11y?

Sagot :

Answer:   -7

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Reason:

The equation −8x−10y=3 is the same as 8x+10y = -3 after multiplying both sides by -1

We have this system of equations

[tex]\begin{cases}-6x+y = -4\\8x+10y = -3\end{cases}[/tex]

Add the equations straight down.

  • -6x+8x becomes 2x
  • y+10y becomes 11y
  • the right hand sides combine to -4+(-3) = -7

Therefore, we end up with the equation 2x+11y = -7

An alternative is to solve the system using substitution to get the (x,y) intersection point. Then use those coordinates to compute 2x+11y and you should get -7 as a result.

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