lngricl
Answered

Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Find the zeros of the function f(x)=x^2+9.9x+18. Round values to the nearest hundredth (if necessary).

Sagot :

A quadratic equation in the form of ax²+bx+c. The zeroes of the polynomial are -2.4 and -7.5.

What is a quadratic equation?

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c. The Root of the quadratic equation are given as,

[tex]x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

The zeroes of the polynomial are:

f(x)=x² + 9.9x + 18

0 = x² + 9.9x + 18

[tex]x= \dfrac{-9.9\pm \sqrt{(9.9)^2-4(1)(18)}}{2(1)}\\\\[/tex]

x = -2.4, -7.5

Hence, the zeroes of the polynomial are -2.4 and -7.5.

Learn more about Quadratic Equations:

https://brainly.com/question/2263981

#SPJ1

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.