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Sagot :
You could answer using a Binomial Distribution but let’s try the sample space
There are a total of 16 possible outcomes
No heads TTTT
One head HTTT, THTT, TTHT, TTTH
Two heads HHTT, HTHT, HTTH, THHT, THTH, TTHH
Three heads HHHT, HHTH, HTHH, THHH
Four heads HHHH
Because P(H) = P(T) they are all equally likely (it is a fair coin)
P(at least 2 heads) = 11/16 = 0.6875
P(exactly 2 heads) = 6/16 = 3/8 = 0.375
P(not all heads) = 1 - P(all heads) = 15/16 = 0.9375
P(more than 2 heads) = 5/16 = 0.3125
There are a total of 16 possible outcomes
No heads TTTT
One head HTTT, THTT, TTHT, TTTH
Two heads HHTT, HTHT, HTTH, THHT, THTH, TTHH
Three heads HHHT, HHTH, HTHH, THHH
Four heads HHHH
Because P(H) = P(T) they are all equally likely (it is a fair coin)
P(at least 2 heads) = 11/16 = 0.6875
P(exactly 2 heads) = 6/16 = 3/8 = 0.375
P(not all heads) = 1 - P(all heads) = 15/16 = 0.9375
P(more than 2 heads) = 5/16 = 0.3125
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