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a. A professional football kicker has a 98.8% probability of successfully kicking an extra point after a touchdown. Assuming statistical independence, what is the probability that this kicker will successfully make all of his next eleven extra point kicks? Round your answer to four decimal places. Probability = b. What is the probability that the kicker will miss at least one of his next eleven extra point kicks? Round your answer to four decimal places. Probability = c. A professional golfer has a 92.75% probability of making a 5-foot putt. Assuming statistical independence, what is the probability that this golfer will successfully make all of his next eight 5-foot putts? Round your answer to four decimal places. Probability = d. What is the probability that the golfer will miss at least one of his next eight 5-foot putts? Round your answer to four decimal places. Probability =

Sagot :

A common discrete distribution used in statistics, as opposed to a continuous distribution is called a Binomial distribution. The probability that the golfer will miss at least one of his next eight 5-foot putts is 0.4523.

What is Binomial distribution?

A common discrete distribution is used in statistics, as opposed to a continuous distribution is called a Binomial distribution. It is given by the formula,

P(x) = ⁿCₓ (pˣ) (q⁽ⁿ⁻ˣ⁾)

Where,

x is the number of successes needed,

n is the number of trials or sample size,

p is the probability of a single success, and

q is the probability of a single failure.

A.) The probability that this kicker will successfully make all of his next eleven extra-point kicks is,

P(x=11) = ¹¹C₁₁ (0.988¹¹) (0.012⁰)

           = 0.8756

B.) The probability that the kicker will miss at least one of his next eleven extra point kicks is,

P(X<11) = 1 - P(X=11)

           = 1 - 0.8756

           = 0.1243

C.) The probability that this golfer will successfully make all of his next eight 5-foot putts is,

P(x=8) = ⁸C₈ (0.9275⁸) (0.0725⁰)

          = 0.5477

D.) The probability that the golfer will miss at least one of his next eight 5-foot putts is,

P(X<8) = 1 - P(X=8)

          = 1 - 0.5477

          = 0.4523

Learn more about Binomial Distribution:

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