Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
[tex]field:x\ \times\ y\\\\ \left\{\begin{array}{ccc}x\cdot y=8000\\2x+2y=400&/:2\end{array}\right\\\left\{\begin{array}{ccc}x\cdot y=8000\\x+y=200&\to x=200-y\end{array}\right\\\\substitute\ to\ x\cdot y=8000\\\\(200-y)\cdot y=8000\\\\-y^2+200y-8000=0\\\\\Delta=b^2-4ac;\ \Delta=200^2-4\cdot(-1)\cdot(-8000)=40000-32000=8000\\\\y_1=\frac{-b-\sqrt\Delta}{2a};\ y_2=\frac{-b+\sqrt\Delta}{2a}[/tex]
[tex]\sqrt\Delta=\sqrt{8000}=\sqrt{1600\cdot5}=40\sqrt5\\\\y_1=\frac{-200-40\sqrt5}{2\cdot(-1)}=\frac{-200-40\sqrt5}{-2}=100+20\sqrt5\approx144.7\ (m)\\\\y_2=\frac{-200+40\sqrt5}{2\cdot(-1)}=\frac{-200+40\sqrt5}{-2}=100-20\sqrt5\approx55.3\ (m)\\\\x_1\approx200-144.7=55.3\ (m)\\\\x_2\approx200-55.3=144.7\ (m)\\\\Answer:Dimension of the field is:55.3m\ \times\ 144.7m[/tex]
[tex]\sqrt\Delta=\sqrt{8000}=\sqrt{1600\cdot5}=40\sqrt5\\\\y_1=\frac{-200-40\sqrt5}{2\cdot(-1)}=\frac{-200-40\sqrt5}{-2}=100+20\sqrt5\approx144.7\ (m)\\\\y_2=\frac{-200+40\sqrt5}{2\cdot(-1)}=\frac{-200+40\sqrt5}{-2}=100-20\sqrt5\approx55.3\ (m)\\\\x_1\approx200-144.7=55.3\ (m)\\\\x_2\approx200-55.3=144.7\ (m)\\\\Answer:Dimension of the field is:55.3m\ \times\ 144.7m[/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.
