Answered

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What are all relative extrema to
f (x)=×^4-32x+4?

Sagot :

konrad509
[tex]f(x)=x^4-32x+4\\ f'(x)=4x^3-32\\\\ 4x^3-32=0\\ 4(x^3-8)=0\\ x=2\\\\ f(2)=2^4-32\cdot2+4=16-64+4=-44[/tex]

The only extremum is [tex]-44[/tex] and it's minimum.
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